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64=64x-16x^2
We move all terms to the left:
64-(64x-16x^2)=0
We get rid of parentheses
16x^2-64x+64=0
a = 16; b = -64; c = +64;
Δ = b2-4ac
Δ = -642-4·16·64
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{64}{32}=2$
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